Mega Code Archive
Leap Year checker
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import sys
import string
def julian_leap(y=2000):
if (y%4) == 0:
return 1
return 0
def gregorian_leap(y=2000):
if (y%400) == 0:
return 1
elif (y%100) == 0:
return 0
elif (y%4) == 0:
return 1
return 0
years = [1999,2000,2001,1900]
print julian_leap()
print gregorian_leap()
if julian_leap():
print "Julian 2000 yes"
if gregorian_leap():
print "Gregorian 2000 yes"
for x in years:
if julian_leap(x):
print "Julian", x, "is leap"
else:
print "Julian", x, "is not leap"
if gregorian_leap(x):
print "Gregorian", x, "is leap"
else:
print "Gregorian", x, "is not leap"
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