Mega Code Archive

 
Categories / Php / Form
 

File Upload Script

<html>  <head>  <title>A File Upload Script</title>  </head>  <body>  <div>  <?php  if ( isset( $_FILES['fupload'] ) ) {      print "name: ".     $_FILES['fupload']['name']       ."<br />";      print "size: ".     $_FILES['fupload']['size'] ." bytes<br />";      print "temp name: ".$_FILES['fupload']['tmp_name']   ."<br />";      print "type: ".     $_FILES['fupload']['type']       ."<br />";      print "error: ".    $_FILES['fupload']['error']      ."<br />";      if ( $_FILES['fupload']['type'] == "image/gif" ) {          $source = $_FILES['fupload']['tmp_name'];          $target = "upload/".$_FILES['fupload']['name'];          move_uploaded_file( $source, $target );// or die ("Couldn't copy");          $size = getImageSize( $target );          $imgstr = "<p><img width=\"$size[0]\" height=\"$size[1]\" ";          $imgstr .= "src=\"$target\" alt=\"uploaded image\" /></p>";          print $imgstr;      }  }  ?>  </div>  <form enctype="multipart/form-data"      action="<?php print $_SERVER['PHP_SELF']?>" method="post">  <p>  <input type="hidden" name="MAX_FILE_SIZE" value="102400" />  <input type="file" name="fupload" /><br/>  <input type="submit" value="upload!" />  </p>  </form>  </body>  </html>