Mega Code Archive
Use Arrays sort to sort an array
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import java.io.File;
import java.io.IOException;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
import java.util.Comparator;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import java.util.Scanner;
public class Anagrams2 {
public static void main(String[] args) {
int minGroupSize = Integer.parseInt(args[1]);
// Read words from file and put into simulated multimap
Map<String, List<String>> m = new HashMap<String, List<String>>();
try {
Scanner s = new Scanner(new File(args[0]));
while (s.hasNext()) {
String word = s.next();
String alpha = alphabetize(word);
List<String> l = m.get(alpha);
if (l == null)
m.put(alpha, l = new ArrayList<String>());
l.add(word);
}
} catch (IOException e) {
System.err.println(e);
System.exit(1);
}
// Make a List of all permutation groups above size threshold
List<List<String>> winners = new ArrayList<List<String>>();
for (List<String> l : m.values())
if (l.size() >= minGroupSize)
winners.add(l);
// Sort permutation groups according to size
Collections.sort(winners, new Comparator<List<String>>() {
public int compare(List<String> o1, List<String> o2) {
return o2.size() - o1.size();
}
});
// Print permutation groups
for (List<String> l : winners) {
System.out.println(l.size() + ": " + l);
}
}
private static String alphabetize(String s) {
char[] a = s.toCharArray();
Arrays.sort(a);
return new String(a);
}
}
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