Mega Code Archive

 

Categories / C# by API / System Windows Forms

 

OpenFileDialog ShowDialog()

using System; using System.Windows.Forms; using System.IO; class MainClass {   public static void Main()    {     OpenFileDialog dlgOpen = new OpenFileDialog();     if (dlgOpen.ShowDialog() == DialogResult.OK)     {       FileInfo fi = new FileInfo(dlgOpen.FileName);       Console.WriteLine("Filename " + fi.FullName );       Console.WriteLine(" Created at " + fi.CreationTime );       Console.WriteLine(" Accessed at " + fi.LastAccessTime );     }   } }