Mega Code Archive
0643 Regex.Escape
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The Regex's Escape and Unescape methods convert a string containing regular expression metacharacters by replacing them with escaped equivalents, and vice versa.
For example:
using System;
using System.Text.RegularExpressions;
class Program
{
static void Main(string[] args)
{
Console.WriteLine(Regex.Escape(@"?"));
Console.WriteLine(Regex.Unescape(@"\?"));
}
}
The output:
\?
?
Without the @, a literal backslash would require four backslashes:
using System;
using System.Text.RegularExpressions;
class Program
{
static void Main(string[] args)
{
Console.WriteLine(Regex.Match("\\", "\\\\"));
}
}
The output:
\
Unless you include the (?x) option, spaces are treated literally in regular expressions:
using System;
using System.Text.RegularExpressions;
class Program
{
static void Main(string[] args)
{
Console.Write(Regex.IsMatch("hello world", @"hello world"));
}
}
The output:
True
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