Mega Code Archive
Transform deque with boolean function
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#include <algorithm>
#include <deque>
#include <iostream>
using namespace std;
bool logical_xor( bool a, bool b );
void print_result( const char* names[], const deque<bool>& print,const char* text );
int main( )
{
const char* contacts[] ={ "A", "J","S", "D", "R" };
const bool salesman1_data[] = { true, true, false, false, true };
const bool salesman2_data[] = { false, false, true, true, true };
const int num_customers = sizeof( salesman1_data ) / sizeof( salesman1_data[0] );
// create deques and initialize with above data
deque<bool> salesman1( salesman1_data,salesman1_data+num_customers );
deque<bool> salesman2( salesman2_data,salesman2_data+num_customers );
deque<bool> result( num_customers );
print_result( contacts, salesman1,"has been called by Salesman 1" );
print_result( contacts, salesman2,"has been called by Salesman 2" );
// customers called by both salesmen
transform( salesman1.begin(), salesman1.end(), salesman2.begin(),result.begin(), logical_and<bool>() );
print_result( contacts, result,"has been called by both salesmen" );
// customers called by at least one salesman
transform( salesman1.begin(), salesman1.end(), salesman2.begin(),result.begin(), logical_or<bool>() );
print_result( contacts, result,"has been called by at least one salesman" );
// customers called by only one salesman
transform( salesman1.begin(), salesman1.end(), salesman2.begin(),result.begin(), logical_xor );
print_result( contacts, result,"has been called by only one salesman" );
// customers not called by Salesman 1
transform( salesman1.begin(), salesman1.end(),result.begin(), logical_not<bool>() );
print_result( contacts, result,"has not been called by Salesman 1" );
}
inline
bool logical_xor( bool a, bool b ) {
return a ? !b : b;
}
void print_result( const char* names[], const deque<bool>& which,const char* text ){
for( deque<bool>::size_type i = 0; i < which.size(); ++i )
if( which[i] )
cout << names[i] << " " << text << endl;
cout << endl;
}
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