Mega Code Archive
Button Column in a asp
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<%@ Page Language=VB Debug=true %>
<%@ Import Namespace="System.Data" %>
<%@ Import Namespace="System.Data.OLEDB" %>
<script runat=server>
Sub Page_Load(ByVal Sender as Object, ByVal E as EventArgs)
If Not IsPostBack Then
Dim DBConn as OleDbConnection
Dim DBCommand As OleDbDataAdapter
Dim DSPageData as New DataSet
DBConn = New OleDbConnection( _
"PROVIDER=Microsoft.Jet.OLEDB.4.0;" _
& "DATA SOURCE=" _
& Server.MapPath("EmployeeDatabase.mdb;"))
DBCommand = New OleDbDataAdapter _
("Select LastName, FirstName, ID From Employee " _
& "Order By LastName, FirstName", DBConn)
DBCommand.Fill(DSPageData, _
"Employee")
dgEmps.DataSource = _
DSPageData.Tables("Employee").DefaultView
dgEmps.DataBind()
End If
End Sub
Sub Click_Grid(ByVal Sender as Object, ByVal E as DataGridCommandEventArgs)
lblMessage.Text = E.Item.Cells(1).Text
End Sub
</SCRIPT>
<HTML>
<HEAD>
<TITLE>Using a ButtonColumn Control in a DataGrid Control</TITLE>
</HEAD>
<Body LEFTMARGIN="40">
<form runat="server">
<BR><BR>
<asp:Label
id="lblMessage"
runat="server"
/>
<BR><BR>
<asp:datagrid
id="dgEmps"
runat="server"
autogeneratecolumns="false"
onitemcommand="Click_Grid"
>
<columns>
<asp:boundcolumn
HeaderText="Full Name"
DataField="LastName"
/>
<asp:boundcolumn
DataField="ID"
Visible=False
/>
<asp:buttoncolumn
HeaderText="Other Fields"
ButtonType="PushButton"
Text="Click to Display Other Fields"
/>
</columns>
</asp:datagrid>
</form>
</BODY>
</HTML>
EmployeeDatabase.zip( 10 k)
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